- A5
- B−8
- C7
- D3
Step-by-Step Solution
Infinitely many solutions need 2/(k − 1) = 3/(k + 2) = 7/(3k). From the first two: 2(k + 2) = 3(k − 1) → 2k + 4 = 3k − 3 → k = 7. Check with the third: 2/6 = 3/9 = 7/21 = 1/3 ✓, so the second equation is exactly 3 times the first. Cross-multiplying the wrong way as 2(k − 1) = 3(k + 2) gives the trap value −8.
Answer: C) 7