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Two dice are thrown simultaneously.
What is the probability that at least one of the dice shows a 6?

Class 10Probability of Simple EventsStatistics

A $\frac{11}{36}$
B $\frac{1}{6}$
C $\frac{1}{3}$
D $\frac{5}{36}$

Step-by-Step Solution

P(no six on either) =

\frac{5}{6} \times \frac{5}{6} = \frac{25}{36}

. P(at least one six) =

1 - \frac{25}{36} = \frac{11}{36}

.

Answer: A)

\frac{11}{36}

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