Three digits are chosen to form a 3-digit number, where each of the digits is independently and equally likely to be any digit from 1 to 9 (no zeros, repeats allowed). What is the probability that all three digits are different?
Class 10Probability Word ProblemsStatistics
A8156
B98
C97
D32
Step-by-Step Solution
Total numbers = 9×9× 9 = 729. All different = 9×8×7=504.P=729504=8156.
Answer: A) 8156
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