In an AP, a_3 = 1/4 and a_4 = 1/3. Find a_12.

1. d = 1/3 - 1/4 = 1/12. a_1 = 1/4 - 2/12 = 1/12. a_12 = 1/12 + 11/12 = 1. (If a_m = 1/n and a_n = 1/m, then a_mn = 1.)

In an AP, $a_{3} = \frac{1}{4}$ and $a_{4} = \frac{1}{3}$ . Find $a_{12}$ .

Class 10Properties and Selection of AP TermsAlgebra — Sequences

d = \frac{1}{3} - \frac{1}{4} = \frac{1}{12} . a_{1} = \frac{1}{4} - \frac{2}{12} = \frac{1}{12} . a_{12} = \frac{1}{12} + \frac{11}{12} = 1

. (If

a_{m} = \frac{1}{n}

and

a_{n} = \frac{1}{m}

, then

a_{mn} = 1.

)

Answer: D) 1

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