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The digits of a three-digit number are in AP and add up to 15. Reversing the digits increases the number by 594. Find the number.

Class 10Properties and Selection of AP TermsAlgebra — Sequences
  • A258
  • B852
  • C357
  • D159

Step-by-Step Solution

Digits 5 − d, 5, 5 + d (sum 15). Number = 100(5 − d) + 50 + (5 + d) = 555 − 99d; reversed = 555 + 99d. Difference 198d = 594, so d = 3: the number is 258 (and 852 − 258 = 594).
Answer: A) 258

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