Practice30Create account

α and β are the roots of . Find the equation whose roots are 2α and 2β.

Class 10Quadratic EquationsAlgebra — Quadratics
  • A
  • B
  • C
  • D

Step-by-Step Solution

α + β = 9 and αβ = 14. The new roots give 2α + 2β = 2(9) = 18 and (2α)(2β) = 4αβ = 4(14) = 56, so the equation is . (Check directly: the original roots are 2 and 7; doubled they are 4 and 14, with sum 18 and product 56.) Option 28 doubles the product instead of multiplying by 4 — the commonest slip here; option 3 doubles only the product; option 4 doubles only the sum.
Answer: B)

Key idea: The discriminant — nature of roots

classifies the roots of **: TWO distinct real roots. Parabola crosses -axis at two points.
- ****: ONE repeated real root (called a 'double root' or 'two equal roots'). Parabola touches -axis at the vertex.
- ****: NO real roots. Parabola does not touch the -axis at all.

**Use case**: 'For what values of does have equal roots?' → set → .

You can answer 'how many real roots?' WITHOUT computing them — just compute .

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Quadratic Equations practice questions

More Class 10 Quadratic Equations practice

The two roots of a quadratic equation are equal in size but opposite in sign, and their…Solve 1/x - 1/x + 4 = 1/3, where x ≠ 0 and x ≠ −4.Solve x⁴ − 13x² + 36 = 0 using the substitution y = x².The equation x - 1/x + 1 + x + 1/x - 1 = 10/3, where x ≠ 1 and x ≠ −1, reduces to which…Two consecutive positive integers are such that their product exceeds their sum by 41.…