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Two consecutive positive integers are such that their product exceeds their sum by 41. Find the LARGER of the two integers.

Class 10Quadratic EquationsAlgebra — Quadratics
  • A7
  • B6
  • C9
  • D8

Step-by-Step Solution

Let the integers be and . Then → → → → (reject −6, since the integers are positive). The pair is 7 and 8: their product 56 exceeds their sum 15 by exactly 41. Answer 7 is the SMALLER integer — the question asked for the larger; 6 keeps the rejected root −6 as a positive answer; 9 fails the check, since exceeds 9 + 10 = 19 by 71, not 41.
Answer: D) 8

Key idea: Word problems with quadratics

Many real-world problems lead to quadratics:

**Number problems**: 'Find two consecutive integers whose product is 132.' Let ; → → or −12. Both valid (or pick positive).

**Area problems**: 'A garden's length is 5 m more than its width. Area is . Find dimensions.'
Let width = . Length = → → (rejecting negative).

**Speed/time/distance**: 'A train takes 1 hour less if its speed is increased by 10 km/h. Original speed?' → typical setup: time1 − time2 = 1 → distance/speed equations → quadratic in speed.

**Always**: reject negative or extraneous roots if context demands positive (lengths, ages, speeds).

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