The difference of squares of two natural numbers is 45. The square of the smaller number is 4 times the larger number. The larger number is:
Find it.

Question

The difference of squares of two natural numbers is 45. The square of the smaller number is 4 times the larger number. The larger number is: Find it.

Accepted Answer

9. Let smaller s, larger L. L^2 - s^2 = 45 and s^2 = 4L. So L^2 - 4L - 45 = 0, (L-9)(L+5)=0. L = 9.

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