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Two squares have sides differing by 4 cm. If the sum of their areas is 400 sq cm, the side of the smaller square is:

Class 10Quadratic Word ProblemsAlgebra — Quadratics

A12 cm
B16 cm
C8 cm
D10 cm

Step-by-Step Solution

x^{2} + (x + 4)^{2} = 400, 2 x^{2} + 8 x - 384 = 0, x^{2} + 4 x - 192 = 0, (x + 16) (x - 12) = 0. x = 12

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Answer: A) 12 cm

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