By factorisation, the quadratic equation abx^2 + (a^2 - b^2)x - ab = 0 (where a, b are nonzero) can be written as (ax - b)(bx + a) = 0. Which are its roots?

Question

Accepted Answer

x = b/a, -a/b. Split the middle term: abx^2 + a^2 x - b^2 x - ab = ax(bx + a) - b(bx + a) = (ax - b)(bx + a) = 0. So ax - b = 0 gives x = b/a, and bx + a = 0 gives x = -a/b.

By factorisation, the quadratic equation $ab$ $x^{2} + (a^{2} - b^{2}) x - ab = 0$ (where a, $b$ are nonzero) can be written as (ax - b) $(b x$ + a) = 0.
Which are its roots?

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More Class 10 Roots by Factorisation practice

By factorisation, the quadratic equation abx2+(a2−b2)x−ab=0 (where a, b are nonzero) can be written as (ax - b)(bx + a) = 0.Which are its roots?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Roots by Factorisation practice

By factorisation, the quadratic equation $ab$ $x^{2} + (a^{2} - b^{2}) x - ab = 0$ (where a, $b$ are nonzero) can be written as (ax - b) $(b x$ + a) = 0.
Which are its roots?