The segment joining A(-2, 1) and B(7, 10) is trisected. Find the point of trisection nearer to B.

The trisection point nearer B divides AB in the ratio 2 : 1. $x=\frac{2\cdot 7+1\cdot (-2)}{3}=\frac{14-2}{3}=4$ and $y=\frac{2\cdot 10+1\cdot 1}{3}=\frac{21}{3}=7$, so the point is (4, 7). (1, 4) is the OTHER trisection point (ratio 1 : 2), obtained by measuring from the wrong end; (2.5, 5.5) is the midpoint, which is not a trisection point at all; (5, 8) is an arithmetic slip.