A garden in Pune is 16 m by 10 m. A uniform path of width x m is built inside along all four sides, leaving an inner rectangle of area 72 sq m. From (16 - 2x)(10 - 2x) = 72, solve by factorisation. What is the path width (in m)?

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Accepted Answer

2. (16-2x)(10-2x) = 72 gives 160 - 52x + 4x^2 = 72, i.e. 4x^2 - 52x + 88 = 0, or x^2 - 13x + 22 = 0 = (x - 2)(x - 11). x = 11 is impossible (exceeds dimensions), so x = 2 m.

A garden in Pune is 16 m by 10 m. A uniform path of width $x$ m is built inside along all four sides, leaving an inner rectangle of area 72 sq m.
From $(16 - 2 x) (10 - 2 x) = 72$ , solve by factorisation. What is the path width (in m)?

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More Class 10 Solving by Factorisation practice

A garden in Pune is 16 m by 10 m. A uniform path of width x m is built inside along all four sides, leaving an inner rectangle of area 72 sq m.From (16−2x)(10−2x)=72, solve by factorisation. What is the path width (in m)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Solving by Factorisation practice

A garden in Pune is 16 m by 10 m. A uniform path of width $x$ m is built inside along all four sides, leaving an inner rectangle of area 72 sq m.
From $(16 - 2 x) (10 - 2 x) = 72$ , solve by factorisation. What is the path width (in m)?