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Splitting the middle term, which values of $x$ satisfy $x^{2} - 7 x + 10 = 0$ ?

Class 10Solving by FactorisationQuadratic Equations

A $x = 2, 5$
B $x = - 2, - 5$
C $x = 1, 10$
D $x = - 1, - 10$

Step-by-Step Solution

−2 and −5 multiply to 10 and add to −7:

x^{2} - 2 x - 5 x + 10 = (x - 2) (x - 5) = 0

, so

x = 2

or

x = 5

.

Answer: A)

x = 2, 5

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