The sum of squares of two consecutive odd positive integers is 130.
Let them be $x$ and $x + 2$ . Form a quadratic and solve by factorisation.
What is the larger integer?

Question

The sum of squares of two consecutive odd positive integers is 130. Let them be x and x + 2. Form a quadratic and solve by factorisation. What is the larger integer?

Accepted Answer

9. x^2 + (x+2)^2 = 130 gives 2x^2 + 4x - 126 = 0, i.e. x^2 + 2x - 63 = 0 = (x + 9)(x - 7). x = 7 (positive odd). Integers are 7 and 9; larger is 9.

The sum of squares of two consecutive odd positive integers is 130.
Let them be $x$ and $x + 2$ . Form a quadratic and solve by factorisation.
What is the larger integer?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Solving by Factorisation practice

The sum of squares of two consecutive odd positive integers is 130.Let them be x and x+2. Form a quadratic and solve by factorisation.What is the larger integer?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Solving by Factorisation practice

The sum of squares of two consecutive odd positive integers is 130.
Let them be $x$ and $x + 2$ . Form a quadratic and solve by factorisation.
What is the larger integer?