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Find the roots of $3$ $x^{2} + 10 x + 7$ $3 = 0$ by factorisation.

Class 10Solving by FactorisationQuadratic Equations

A $x = - 3, - \frac{7}{3}$
B $x = 3, \frac{7}{3}$
C $x = - 3, \frac{7}{3}$
D $x = 3, - \frac{7}{3}$

Step-by-Step Solution

Product =

3 * 73 = 21

, sum = 10, split as 3 + 7.

3

x^{2} + 3 x + 7 x + 7

3 = 3

x (x + 3) + 7 (x + 3) = (x + 3) (3

x + 7

) = 0. So

x = - 3

or

x = - \frac{7}{3}

.

Answer: A)

x = - 3, - \frac{7}{3}

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