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Expand, rearrange and factorise to solve $(x - 3) (x + 2) = 14$ .

Class 10Solving by FactorisationQuadratic Equations

A $x = 5, - 4$
B $x = 3, - 2$
C $x = 4, - 5$
D $x = 7, 2$

Step-by-Step Solution

Expand:

x^{2} - x - 6 = 14

, so

x^{2} - x - 20 = 0 = (x - 5) (x + 4) . x = 5

or

x = - 4

.

Answer: A)

x = 5, - 4

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