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Rewrite $(2 x - 1)^{2} = 9$ with zero on one side and solve it by factorisation.

Class 10Solving by FactorisationQuadratic Equations

A $x = 2, - 1$
B $x = 1, - 2$
C $x = 3, - 3$
D $x = 2, 1$

Step-by-Step Solution

(2 x - 1)^{2} - 9 = 0 = (2 x - 1 - 3) (2 x - 1 + 3) = (2 x - 4) (2 x + 2) . S o x = 2 or x = - 1

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Answer: A)

x = 2, - 1

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