The diagonal of a rectangular field is 17 m and one side is 7 m longer than the other. Let the shorter side be x m. Using the diagonal relation x^2 + (x+7)^2 = 17^2, solve by factorisation. What is the longer side (in m)?

Question

Accepted Answer

15. 2x^2 + 14x - 240 = 0, i.e. x^2 + 7x - 120 = 0 = (x + 15)(x - 8). x = 8, so longer side = 8 + 7 = 15 m.

The diagonal of a rectangular field is 17 m and one side is 7 m longer than the other.
Let the shorter side be $x$ m. Using the diagonal relation $x^{2} + (x + 7)^{2} = 1 7^{2}$ , solve by factorisation.
What is the longer side (in m)?

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More Class 10 Solving by Factorisation practice

The diagonal of a rectangular field is 17 m and one side is 7 m longer than the other.Let the shorter side be x m. Using the diagonal relation x2+(x+7)2=172, solve by factorisation.What is the longer side (in m)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Solving by Factorisation practice

The diagonal of a rectangular field is 17 m and one side is 7 m longer than the other.
Let the shorter side be $x$ m. Using the diagonal relation $x^{2} + (x + 7)^{2} = 1 7^{2}$ , solve by factorisation.
What is the longer side (in m)?