A rectangular plot in Jaipur has length 3 m more than its width. Its area is 70 sq m. Let the width be x m, so length = (x + 3) m. Form and solve a quadratic by factorisation to find the width (in m).

Question

Accepted Answer

7. x(x + 3) = 70, i.e. x^2 + 3x - 70 = 0 = (x + 10)(x - 7). x = 7 (reject -10). Width = 7 m.

A rectangular plot in Jaipur has length 3 m more than its width. Its area is 70 sq m.
Let the width be $x$ m, so length = $(x + 3)$ m.
Form and solve a quadratic by factorisation to find the width (in m).

Step-by-Step Solution

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More Class 10 Solving by Factorisation practice

A rectangular plot in Jaipur has length 3 m more than its width. Its area is 70 sq m.Let the width be x m, so length = (x+3) m.Form and solve a quadratic by factorisation to find the width (in m).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Solving by Factorisation practice

A rectangular plot in Jaipur has length 3 m more than its width. Its area is 70 sq m.
Let the width be $x$ m, so length = $(x + 3)$ m.
Form and solve a quadratic by factorisation to find the width (in m).