A train travels 360 km. Mr. Sharma observes that if the average speed were 5 km/h more, the journey would take 1 hour less. This leads to the equation x^2 + 5x - 1800 = 0, where x is the original speed. What is the original speed in km/h?

Question

Accepted Answer

40. x^2 + 5x - 1800 = 0 factors as (x - 40)(x + 45) = 0, giving x = 40 or x = -45. Speed is positive, so x = 40 km/h.

A train travels 360 km. Mr. Sharma observes that if the average speed were 5 km/h more, the journey would take 1 hour less.
This leads to the equation $x^{2} + 5 x - 1800 = 0$ , where $x$ is the original speed.
What is the original speed in km/h?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

A train travels 360 km. Mr. Sharma observes that if the average speed were 5 km/h more, the journey would take 1 hour less.This leads to the equation x2+5x−1800=0, where x is the original speed.What is the original speed in km/h?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

A train travels 360 km. Mr. Sharma observes that if the average speed were 5 km/h more, the journey would take 1 hour less.
This leads to the equation $x^{2} + 5 x - 1800 = 0$ , where $x$ is the original speed.
What is the original speed in km/h?