The table shows the marks of some students in a test, but one frequency is written as p. The mean of the data is 48. Find p.
Class 10StatisticsStatistics and Probability
A12
B10
C8
D15
Step-by-Step Solution
Class marks 10,30,50,70,90.∑fx=70+240+50p+840+270=1420+50p and ∑f=30+p. So 48(30+p)=1420+50p⇒1440+48p=1420+50p⇒p=10.
Answer: B) 10
Key idea: Median for grouped data
**Step 1**: build cumulative frequency (cf) column. **Step 2**: find n/2 (half the total frequency). **Step 3**: locate the **median class** — the FIRST class whose cumulative frequency ≥ n/2. **Step 4**: Apply formula.
**Median formula**: **Median = l + h × (n/2 − cf) / f**
Where: - l = lower limit of median class - h = class width - n = total frequency - cf = cumulative frequency of class BEFORE median class - f = frequency of median class
The formula uses linear interpolation within the median class to find where the n/2-th item falls.
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