A cuboidal box 10 cm x 10 cm x 24 cm has a hemisphere (radius 5 cm) fixed centrally on its top face (10 x 10). The surface to be wrapped = TSA of cuboid - top circle of hemisphere + curved hemisphere surface. In cm^2 (π = 3.14): (CSA = curved surface area, TSA = total surface area)

Question

Accepted Answer

1238.5. TSA cuboid = 2(10*10 + 10*24 + 24*10) = 2(100 + 240 + 240) = 2*580 = 1160. Top circle = π*r^2 = 3.14*25 = 78.5. Hemisphere CSA = 2*π*r^2 = 157. Total = 1160 - 78.5 + 157 = 1238.5 cm^2.

A cuboidal box 10 cm $x$ 10 cm $x$ 24 cm has a hemisphere (radius 5 cm) fixed centrally on its top face $(10 \times 10)$ . The surface to be wrapped = TSA of cuboid - top circle of hemisphere + curved hemisphere surface. In $cm^{2}$ (π = 3.14): (CSA = curved surface area, TSA = total surface area)

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More Class 10 Surface Area of Combined Solids practice

A cuboidal box 10 cm x 10 cm x 24 cm has a hemisphere (radius 5 cm) fixed centrally on its top face (10×10). The surface to be wrapped = TSA of cuboid - top circle of hemisphere + curved hemisphere surface. In cm2 (π = 3.14): (CSA = curved surface area, TSA = total surface area)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Surface Area of Combined Solids practice

A cuboidal box 10 cm $x$ 10 cm $x$ 24 cm has a hemisphere (radius 5 cm) fixed centrally on its top face $(10 \times 10)$ . The surface to be wrapped = TSA of cuboid - top circle of hemisphere + curved hemisphere surface. In $cm^{2}$ (π = 3.14): (CSA = curved surface area, TSA = total surface area)