A medicine capsule is 14 mm long overall and 5 mm in diameter (so r = 2.5 mm). The cylindrical part length = 14 - 2*2.5 = 9 mm. Its surface area (2*π*r*h + 4*π*r^2) in mm^2, taking π = 22/7, is approximately:

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Accepted Answer

220 mm^2. 2*π*r*h = 2*(22/7)*2.5*9 = 141.43. 4*π*r^2 = 4*(22/7)*6.25 = 78.57. Total = 141.43+78.57 = 220 mm^2.

A medicine capsule is 14 mm long overall and 5 mm in diameter (so $r = 2.5$ mm). The cylindrical part length = 14 - 22.5 = 9 mm. Its surface area (2π* $r * h + 4$ π $r^{2}$ ) in $mm^{2}$ , taking π = $\frac{22}{7}$ , is approximately:

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More Class 10 Surface Area of Combined Solids practice

A medicine capsule is 14 mm long overall and 5 mm in diameter (so r=2.5 mm). The cylindrical part length = 14 - 2*2.5 = 9 mm. Its surface area (2*π*r∗h+4*π*r2) in mm2, taking π = 722​, is approximately:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Surface Area of Combined Solids practice

A medicine capsule is 14 mm long overall and 5 mm in diameter (so $r = 2.5$ mm). The cylindrical part length = 14 - 22.5 = 9 mm. Its surface area (2π* $r * h + 4$ π $r^{2}$ ) in $mm^{2}$ , taking π = $\frac{22}{7}$ , is approximately: