- A36 cm
- B12 cm
- C48 cm
- D24 cm
Step-by-Step Solution
CQ = CA and DQ = DB (equal tangents). Perimeter = PC + CQ + QD + DP = (PC + CA) + (DB + DP) = PA + PB = 24 cm.
Answer: D) 24 cm
PA and PB are tangents of length 12 cm. A third tangent touches the circle at Q, between A and B, and cuts PA at C and PB at D. Find the perimeter of triangle PCD.
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