For (k+1)x^2 - 6(k+1)x + 3(k+9) = 0 (k not -1) to have equal roots, find the value of k.

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3. Equal roots: D = 0. [6(k+1)]^2 - 4(k+1)(3)(k+9) = 0 => 36(k+1)^2 - 12(k+1)(k+9) = 0 => 12(k+1)[3(k+1) - (k+9)] = 0 => 12(k+1)(2k - 6) = 0. Since k not -1, 2k - 6 = 0 => k = 3.

For $(k + 1) x^{2} - 6 (k + 1) x + 3 (k + 9) = 0 (k$ not -1) to have equal roots, find the value of $k$ .

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More Class 10 The Quadratic Formula practice

For (k+1)x2−6(k+1)x+3(k+9)=0(k not -1) to have equal roots, find the value of k.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

For $(k + 1) x^{2} - 6 (k + 1) x + 3 (k + 9) = 0 (k$ not -1) to have equal roots, find the value of $k$ .