Solve abx^2 + (b^2 - ac) x - bc = 0 for x using the quadratic formula (a, b, c are constants, ab != 0). The two roots are:

Question

Accepted Answer

c/b and -b/a. D = (b^2 - ac)^2 + 4ab · bc = (b^2 - ac)^2 + 4ab^2c = (b^2 + ac)^2. √D = b^2 + ac. x = -(b^2 - ac) ± (b^2 + ac)/2ab = 2ac/2ab = c/b or -2b^2/2ab = -b/a.

Solve $ab$ $x^{2} + (b^{2} - a c) x - b c = 0$ for $x$ using the quadratic formula
(a, $b, c$ are constants, $ab$ != 0). The two roots are:

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More Class 10 The Quadratic Formula practice

Solve abx2+(b2−ac)x−bc=0 for x using the quadratic formula(a, b,c are constants, ab != 0). The two roots are:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

Solve $ab$ $x^{2} + (b^{2} - a c) x - b c = 0$ for $x$ using the quadratic formula
(a, $b, c$ are constants, $ab$ != 0). The two roots are: