The sum of the squares of two consecutive even numbers is 340. If the smaller number is x, which equation should you solve?

Question

Accepted Answer

x^2 + 2x - 168 = 0. x^2 + (x + 2)^2 = 340 => 2x^2 + 4x + 4 = 340 => 2x^2 + 4x - 336 = 0 => x^2 + 2x - 168 = 0. (D = 4 + 672 = 676, √D = 26, x = 12, so the numbers are 12 and 14.)

The sum of the squares of two consecutive even numbers is 340.
If the smaller number is $x$ , which equation should you solve?

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The sum of the squares of two consecutive even numbers is 340.If the smaller number is x, which equation should you solve?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

The sum of the squares of two consecutive even numbers is 340.
If the smaller number is $x$ , which equation should you solve?