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If alpha and beta are the zeroes of $x^{2} - 6 x + k$ and alph $a^{2}$ + bet $a^{2} = 40$ , find the value of $k$ .

Class 10Zeroes and CoefficientsAlgebra — Polynomials

A-4
B-1
C-2
D-3

Step-by-Step Solution

alph

a^{2}

+ bet

a^{2} = (s u m)^{2} - 2

(product).

40 = 36 - 2 k

, so

2 k = 36 - 40 = - 4, k = - 2

.

Answer: C) -2

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