A bridge cable in a Mumbai design dips along the curve y = x^2 - 6x + 5 (in suitable units). The cable meets the road level (y = 0) at two points. What is the distance between these two points along the x-axis?

Question

Accepted Answer

4. x^2 - 6x + 5 = (x - 1)(x - 5), zeroes at x = 1 and x = 5. Distance = 5 - 1 = 4 units.

A bridge cable in a Mumbai design dips along the curve $y = x^{2} - 6 x + 5$ (in suitable units).
The cable meets the road level $(y = 0)$ at two points. What is the distance between these two points along the $x$ -axis?

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More Class 10 Zeroes of a Polynomial practice

A bridge cable in a Mumbai design dips along the curve y=x2−6x+5 (in suitable units).The cable meets the road level (y=0) at two points. What is the distance between these two points along the x-axis?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Zeroes of a Polynomial practice

A bridge cable in a Mumbai design dips along the curve $y = x^{2} - 6 x + 5$ (in suitable units).
The cable meets the road level $(y = 0)$ at two points. What is the distance between these two points along the $x$ -axis?