Anita has 84 red beads and 90 blue beads. She makes the largest possible identical bracelets using all beads, each bracelet having the same number of red beads and the same number of blue beads. How many bracelets can she make?

Question

Accepted Answer

6. We need HCF(84,90). 84 = 2x2x3x7, 90 = 2x3x3x5. Common = 2x3 = 6. So 6 bracelets.

Anita has 84 red beads and 90 blue beads.
She makes the largest possible identical bracelets using all beads, each bracelet having the same number of red beads and the same number of blue beads.
How many bracelets can she make?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 6 Factors and Multiples practice

Anita has 84 red beads and 90 blue beads.She makes the largest possible identical bracelets using all beads, each bracelet having the same number of red beads and the same number of blue beads.How many bracelets can she make?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 6 Factors and Multiples practice

Anita has 84 red beads and 90 blue beads.
She makes the largest possible identical bracelets using all beads, each bracelet having the same number of red beads and the same number of blue beads.
How many bracelets can she make?