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Find the least number which when divided by 15, 20 and 35 leaves a remainder of 8 in each case.

Class 6HCF and LCMPlaying with Numbers

A428
B420
C412
D440

Step-by-Step Solution

LCM(15,20,35):

15 = 3 \times 5, 20 = 2^{2} x 5, 35 = 5 \times 7

, LCM =

2^{2} x 3 x 5 x 7 = 420

. Add remainder 8: 420 + 8 = 428.

Answer: A) 428

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