- A₹81000
- B₹4500
- C₹18000
- D₹9000
Step-by-Step Solution
A fence follows the boundary, so use the PERIMETER: m. Cost = 150 × ₹60 = ₹9000. Charging by the AREA × ₹60) gives the trap ₹81000; using only (45 + 30) gives ₹4500.
Answer: D) ₹9000
A rectangular plot in Nashik is 45 m long and 30 m wide. Barbed wire fencing costs ₹60 per metre. Find the cost of fencing the plot once all around.
Class 7Perimeter and AreaPerimeter and Area
Key idea: Parallelogram area
**Area of a parallelogram = base × height.**
Same idea as a rectangle, but the height is the perpendicular distance between the two parallel sides — NOT the slant length of the side. Pick any side as the base, drop a perpendicular to the opposite parallel side, measure that — that's the height.
Example: parallelogram with base 8 cm and perpendicular height 5 cm. Area = . The slant side could be longer; doesn't matter for area.
Perimeter of a parallelogram = 2 × (one side + adjacent side).
Same idea as a rectangle, but the height is the perpendicular distance between the two parallel sides — NOT the slant length of the side. Pick any side as the base, drop a perpendicular to the opposite parallel side, measure that — that's the height.
Example: parallelogram with base 8 cm and perpendicular height 5 cm. Area = . The slant side could be longer; doesn't matter for area.
Perimeter of a parallelogram = 2 × (one side + adjacent side).
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