Priya divides the segment from 0 to 1 into equal parts and finds 7/10 falls on a marked point with no further splitting needed. What is the smallest number of equal parts she could have used?

Question

Accepted Answer

10. 7/10 is already in lowest terms, so the denominator 10 is the smallest number of equal parts needed.

Priya divides the segment from 0 to 1 into equal parts and finds $\frac{7}{10}$ falls on a marked point with no further splitting needed.
What is the smallest number of equal parts she could have used?

Step-by-Step Solution

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More Class 7 Rational Numbers on the Number Line practice

Priya divides the segment from 0 to 1 into equal parts and finds 107​ falls on a marked point with no further splitting needed.What is the smallest number of equal parts she could have used?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Rational Numbers on the Number Line practice

Priya divides the segment from 0 to 1 into equal parts and finds $\frac{7}{10}$ falls on a marked point with no further splitting needed.
What is the smallest number of equal parts she could have used?