A number is 2^3 x 3^3 x 5^3 x 7. By what smallest number should it be DIVIDED so that the result is a perfect cube, and what is the cube root of that result?

Question

Accepted Answer

divide by 7, cube root 30. The prime 7 appears once (not a triple). Divide by 7 to remove it. The remainder 2^3 x 3^3 x 5^3 = 30^3, so cube root = 30.

A number is $2^{3} \times 3^{3} \times 5^{3} \times$ 7.
By what smallest number should it be DIVIDED so that the result is a perfect cube, and what is the cube root of that result?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Cube Root by Prime Factorisation practice

A number is 23×33×53× 7.By what smallest number should it be DIVIDED so that the result is a perfect cube, and what is the cube root of that result?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Cube Root by Prime Factorisation practice

A number is $2^{3} \times 3^{3} \times 5^{3} \times$ 7.
By what smallest number should it be DIVIDED so that the result is a perfect cube, and what is the cube root of that result?