A pattern of consecutive odd numbers builds cubes. The block that sums to 6^3 starts at the odd number 31 (since the previous blocks used up odd numbers 1 to 29). How many odd numbers are in this block for 6^3?

Question

Accepted Answer

6. n^3 is the sum of n consecutive odd numbers, so 6^3 uses 6 odd numbers (31+33+35+37+39+41 = 216).

A pattern of consecutive odd numbers builds cubes. The block that sums to $6^{3}$ starts at the odd number 31 (since the previous blocks used up odd numbers 1 to 29).
How many odd numbers are in this block for $6^{3}$ ?

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More Class 8 Patterns in Cubes practice

A pattern of consecutive odd numbers builds cubes. The block that sums to 63 starts at the odd number 31 (since the previous blocks used up odd numbers 1 to 29).How many odd numbers are in this block for 63?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Patterns in Cubes practice

A pattern of consecutive odd numbers builds cubes. The block that sums to $6^{3}$ starts at the odd number 31 (since the previous blocks used up odd numbers 1 to 29).
How many odd numbers are in this block for $6^{3}$ ?