The sum of the first n odd numbers is n², a square. A cube can also be written as a sum of consecutive odd numbers: 27 = 3³ is the sum of 3 consecutive odd numbers. Which group is it?

Question

Accepted Answer

7 + 9 + 11. 7 + 9 + 11 = 27 = 3^3. (This is the known pattern: n^3 is a sum of n consecutive odd numbers; for 3^3 the three odds are 7, 9, 11.)

The sum of the first $n$ odd numbers is $n^{2}$ , a square. A cube can also be written as a sum of consecutive odd numbers: $27 = 3^{3}$ is the sum of 3 consecutive odd numbers. Which group is it?

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More Class 8 Perfect Cubes practice

The sum of the first n odd numbers is n2, a square. A cube can also be written as a sum of consecutive odd numbers: 27=33 is the sum of 3 consecutive odd numbers. Which group is it?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Perfect Cubes practice

The sum of the first $n$ odd numbers is $n^{2}$ , a square. A cube can also be written as a sum of consecutive odd numbers: $27 = 3^{3}$ is the sum of 3 consecutive odd numbers. Which group is it?