In parallelogram ABCD, angle A = (5x - 5) deg and the adjacent angle B = (3x + 25) deg. Using the property that adjacent angles are supplementary, find angle A (in degrees).

Question

Accepted Answer

95. A + B = 180: (5x - 5) + (3x + 25) = 180, so 8x + 20 = 180, 8x = 160, x = 20. angle A = 5(20) - 5 = 95°.

In parallelogram ABCD, angle $A = (5 x - 5)$ deg and the adjacent angle $B = (3 x + 25)$ deg.
Using the property that adjacent angles are supplementary, find angle A (in degrees).

Step-by-Step Solution

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More Class 8 Properties of Quadrilaterals practice

In parallelogram ABCD, angle A=(5x−5) deg and the adjacent angle B=(3x+25) deg.Using the property that adjacent angles are supplementary, find angle A (in degrees).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Properties of Quadrilaterals practice

In parallelogram ABCD, angle $A = (5 x - 5)$ deg and the adjacent angle $B = (3 x + 25)$ deg.
Using the property that adjacent angles are supplementary, find angle A (in degrees).