A Pythagorean triplet is built using the form 2$m,m^2-1,m^2+1$. If the smallest member of the triplet is 12, what are the other two members?

Pair digits from the **decimal point outward** — that is, leftward for the integer part, rightward for the decimal part. Add zeros on the right of the decimal as needed to make full pairs.

Example: $\sqrt{0.0625}$. Pair: .06 25. The integer part is empty. Apply long division on the paired form. Result: 0.25 (since $0.25^2=0.0625$).