A road roller is 120 cm long with diameter 84 cm. It takes 500 complete revolutions to level a playground once. Find the area of the playground. (Take π = 22/7.)

Question

Accepted Answer

1584 sq m. Area per revolution = 2 × 22/7 × 42 × 120 = 31680 sq cm. For 500 revolutions: 15840000 sq cm = 1584 sq m (1 sq m = 10000 sq cm).

A road roller is 120 cm long with diameter 84 cm. It takes 500 complete revolutions to level a playground once. Find the area of the playground. (Take π = $\frac{22}{7} .$ )

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Surface Area of a Cylinder practice

A road roller is 120 cm long with diameter 84 cm. It takes 500 complete revolutions to level a playground once. Find the area of the playground. (Take π = 722​.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Surface Area of a Cylinder practice

A road roller is 120 cm long with diameter 84 cm. It takes 500 complete revolutions to level a playground once. Find the area of the playground. (Take π = $\frac{22}{7} .$ )