A rhombus-shaped field is divided by a diagonal into two triangles. One triangle has sides 30 $m, 30 m$ and 48 $m$ (the diagonal).
Find the area of the whole rhombus (in $m^{2}$ ).

Question

A rhombus-shaped field is divided by a diagonal into two triangles. One triangle has sides 30 m, 30 m and 48 m (the diagonal). Find the area of the whole rhombus (in m^2).

Accepted Answer

864. s of one triangle = 30+30+48/2 = 54. Area = √54 · 24 · 24 · 6 = √186624 = 432 m^2. Rhombus = 2 triangles = 2 · 432 = 864 m^2.

A rhombus-shaped field is divided by a diagonal into two triangles. One triangle has sides 30 $m, 30 m$ and 48 $m$ (the diagonal).
Find the area of the whole rhombus (in $m^{2}$ ).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

A rhombus-shaped field is divided by a diagonal into two triangles. One triangle has sides 30 m,30m and 48 m (the diagonal).Find the area of the whole rhombus (in m2).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

A rhombus-shaped field is divided by a diagonal into two triangles. One triangle has sides 30 $m, 30 m$ and 48 $m$ (the diagonal).
Find the area of the whole rhombus (in $m^{2}$ ).