The perimeter of a triangular field is 540 $m$ and its sides are in the ratio 25 : 17 : 12.
Find the area of the field (in $m^{2}$ ).

Question

The perimeter of a triangular field is 540 m and its sides are in the ratio 25 : 17 : 12. Find the area of the field (in m^2).

Accepted Answer

9000. Sum of ratio parts = 25+17+12 = 54. Each part = 540/54 = 10. Sides: 250, 170, 120 m. s = 270. Area = √270 · 20 · 100 · 150 = √81000000 = 9000 m^2.

The perimeter of a triangular field is 540 $m$ and its sides are in the ratio 25 : 17 : 12.
Find the area of the field (in $m^{2}$ ).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

The perimeter of a triangular field is 540 m and its sides are in the ratio 25 : 17 : 12.Find the area of the field (in m2).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

The perimeter of a triangular field is 540 $m$ and its sides are in the ratio 25 : 17 : 12.
Find the area of the field (in $m^{2}$ ).