In the diagram, ABCD is a parallelogram of area 100 cm^2 and P is the point where the diagonals meet. The two diagonals divide the parallelogram into four triangles. The area of each of these four triangles (in cm^2) is:

Question

Accepted Answer

25. The diagonals of a parallelogram bisect each other and split it into four triangles of equal area, each = 100/4 = 25 cm^2.

In the diagram, ABCD is a parallelogram of area $100 cm^{2}$ and P is the point where the diagonals meet. The two diagonals divide the parallelogram into four triangles. The area of each of these four triangles (in $cm^{2}$ ) is:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Areas — Figures on the Same Base practice

In the diagram, ABCD is a parallelogram of area 100cm2 and P is the point where the diagonals meet. The two diagonals divide the parallelogram into four triangles. The area of each of these four triangles (in cm2) is:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Areas — Figures on the Same Base practice

In the diagram, ABCD is a parallelogram of area $100 cm^{2}$ and P is the point where the diagonals meet. The two diagonals divide the parallelogram into four triangles. The area of each of these four triangles (in $cm^{2}$ ) is: