In the figure, parallelogram ABCD has base AB = 16 cm. A road designer draws triangle PAB where P is any point on the line through D and C (the line parallel to AB). The perpendicular distance between AB and that line is 9 cm. Find the area of triangle PAB in cm^2.

Question

Accepted Answer

72. P is on the parallel through DC, so triangle PAB lies on base AB between the same parallels. Its height = 9 cm. Area = 1/2(16)(9) = 72 cm^2.

In the figure, parallelogram ABCD has base AB = 16 cm. A road designer draws triangle PAB where P is any point on the line through D and C (the line parallel to AB).
The perpendicular distance between AB and that line is 9 cm.
Find the area of triangle PAB in $cm^{2}$ .

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More Class 9 Areas — Figures on the Same Base practice

In the figure, parallelogram ABCD has base AB = 16 cm. A road designer draws triangle PAB where P is any point on the line through D and C (the line parallel to AB).The perpendicular distance between AB and that line is 9 cm.Find the area of triangle PAB in cm2.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Areas — Figures on the Same Base practice

In the figure, parallelogram ABCD has base AB = 16 cm. A road designer draws triangle PAB where P is any point on the line through D and C (the line parallel to AB).
The perpendicular distance between AB and that line is 9 cm.
Find the area of triangle PAB in $cm^{2}$ .