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A teacher writes: AB = CD. A student adds the SAME segment PQ to AB to form AB + PQ, and adds PQ to CD to form CD + PQ.
What is the correct conclusion and the supporting axiom?

Class 9Euclid's AxiomsGeometry — Foundations
  • AAB + PQ = CD + PQ, by adding equals to equals
  • BAB + PQ > CD + PQ, by whole greater than part
  • CAB + PQ = CD, by coincidence
  • DAB + PQ < CD + PQ, by subtraction axiom

Step-by-Step Solution

AB = CD; adding the same PQ to both equals keeps them equal: AB + PQ = CD + PQ (if equals are added to equals, the wholes are equal).
Answer: A) AB + PQ = CD + PQ, by adding equals to equals

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