Deepak factorises p(x) = 2x^3 - x^2 - 2x + 1 by grouping. He writes it as x^2(2x - 1) - 1(2x - 1). What is the complete factorisation?

Question

Accepted Answer

(2x - 1)(x - 1)(x + 1). x^2(2x - 1) - 1(2x - 1) = (2x - 1)(x^2 - 1) = (2x - 1)(x - 1)(x + 1). The first option gives the fully factored form.

Deepak factorises $p (x) = 2 x^{3} - x^{2} - 2 x + 1$ by grouping.
He writes it as $x^{2} (2 x - 1) - 1 (2 x - 1)$ .
What is the complete factorisation?