The cost of a taxi ride is given by y = 12x + 50, where x is km and y is rupees. Using the graph, by how many rupees does the fare increase when the distance increases from 3 km to 5 km?

Question

Accepted Answer

24. Fare at 5 km: 12(5)+50 = 110. Fare at 3 km: 12(3)+50 = 86. Increase = 110 - 86 = 24 rupees.

The cost of a taxi ride is given by $y = 12 x + 50$ , where $x$ is km and $y$ is rupees.
Using the graph, by how many rupees does the fare increase when the distance increases from 3 km to 5 km?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Graph of a Linear Equation practice

The cost of a taxi ride is given by y=12x+50, where x is km and y is rupees.Using the graph, by how many rupees does the fare increase when the distance increases from 3 km to 5 km?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Graph of a Linear Equation practice

The cost of a taxi ride is given by $y = 12 x + 50$ , where $x$ is km and $y$ is rupees.
Using the graph, by how many rupees does the fare increase when the distance increases from 3 km to 5 km?