ABCD is a parallelogram in which the bisector of angle A meets BC at E.
If angle A = 70°, show angle AEB equals angle EAB and find angle AEB (in degrees).

Question

ABCD is a parallelogram in which the bisector of angle A meets BC at E. If angle A = 70°, show angle AEB equals angle EAB and find angle AEB (in degrees).

Accepted Answer

35. AD || BC, transversal AE gives angle DAE = angle AEB (alternate). The bisector makes angle DAE = angle EAB = 35°, so angle AEB = 35°.

ABCD is a parallelogram in which the bisector of angle A meets BC at E.
If angle A = 70°, show angle AEB equals angle EAB and find angle AEB (in degrees).

Step-by-Step Solution

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More Class 9 Properties of a Parallelogram practice

ABCD is a parallelogram in which the bisector of angle A meets BC at E.If angle A = 70°, show angle AEB equals angle EAB and find angle AEB (in degrees).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Properties of a Parallelogram practice

ABCD is a parallelogram in which the bisector of angle A meets BC at E.
If angle A = 70°, show angle AEB equals angle EAB and find angle AEB (in degrees).