Asha is checking whether (x - 2) divides p(x) = x^3 - 6x^2 + 11x - 6 exactly. She uses the Remainder Theorem instead of long division. What remainder does she get, and does (x - 2) divide p(x) exactly?

Question

Accepted Answer

Remainder 0, yes it divides exactly. p(2) = 8 - 24 + 22 - 6 = 0. Since the remainder is 0, (x - 2) divides p(x) exactly.

Asha is checking whether $(x - 2)$ divides $p (x) = x^{3} - 6 x^{2} + 11 x - 6$ exactly.
She uses the Remainder Theorem instead of long division.
What remainder does she get, and does $(x - 2)$ divide $p (x)$ exactly?

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More Class 9 Remainder Theorem practice

Asha is checking whether (x−2) divides p(x)=x3−6x2+11x−6 exactly.She uses the Remainder Theorem instead of long division.What remainder does she get, and does (x−2) divide p(x) exactly?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Remainder Theorem practice

Asha is checking whether $(x - 2)$ divides $p (x) = x^{3} - 6 x^{2} + 11 x - 6$ exactly.
She uses the Remainder Theorem instead of long division.
What remainder does she get, and does $(x - 2)$ divide $p (x)$ exactly?