When the polynomial p(x) = x^2 + bx + c is divided by (x - 1) the remainder is 6, and when divided by (x + 1) the remainder is 2. Using these two facts, find the value of b.

Question

Accepted Answer

2. p(1) = 1 + b + c = 6 so b + c = 5. p(-1) = 1 - b + c = 2 so -b + c = 1. Subtracting: 2b = 4, b = 2.

When the polynomial $p (x) = x^{2} + b x + c$ is divided by $(x - 1)$ the remainder is 6, and when divided by $(x + 1)$ the remainder is 2.
Using these two facts, find the value of $b$ .

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More Class 9 Remainder Theorem practice

When the polynomial p(x)=x2+bx+c is divided by (x−1) the remainder is 6, and when divided by (x+1) the remainder is 2.Using these two facts, find the value of b.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Remainder Theorem practice

When the polynomial $p (x) = x^{2} + b x + c$ is divided by $(x - 1)$ the remainder is 6, and when divided by $(x + 1)$ the remainder is 2.
Using these two facts, find the value of $b$ .