When p(x) is divided by (x - 1) the remainder is 4 and when divided by (x - 2) the remainder is 9. If p(x) is divided by (x - 1)(x - 2), the remainder has the form rx + s (a linear remainder). Find the value of r.

Question

Accepted Answer

5. The linear remainder R(x) = rx + s satisfies R(1) = p(1) = 4 and R(2) = p(2) = 9. So r + s = 4 and 2r + s = 9. Subtracting: r = 5.

When p $(x)$ is divided by $(x - 1)$ the remainder is 4 and when divided by $(x - 2)$ the remainder is 9.
If p $(x)$ is divided by $(x - 1) (x - 2)$ , the remainder has the form rx + s (a linear remainder).
Find the value of r.

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More Class 9 Remainder Theorem practice

When p(x) is divided by (x−1) the remainder is 4 and when divided by (x−2) the remainder is 9.If p(x) is divided by (x−1)(x−2), the remainder has the form rx + s (a linear remainder).Find the value of r.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Remainder Theorem practice

When p $(x)$ is divided by $(x - 1)$ the remainder is 4 and when divided by $(x - 2)$ the remainder is 9.
If p $(x)$ is divided by $(x - 1) (x - 2)$ , the remainder has the form rx + s (a linear remainder).
Find the value of r.